冰雹猜想 | 程式專案 | 橘蘋學習平台

{"id":296786,"student_id":3311,"content":"{\"html\":\"\u003c!DOCTYPE html\u003e\\n\u003chtml\u003e\\n\u003chead\u003e\\n\\t\u003ctitle\u003eDocument\u003c/title\u003e\\n\\t\u003cscript src=\\\"https://code.jquery.com/jquery-3.2.1.min.js\\\"\u003e\u003c/script\u003e\\n\u003c/head\u003e\\n\u003cbody\u003e\\n    \u003cinput id=\\\"math\\\"\u003e\\n    \u003cbutton id=\\\"swan\\\"\u003e算\u003c/button\u003e\\n\u003c/body\u003e\\n\u003c/html\u003e\",\"css\":\"input {\\r\\n    height: 40px;\\r\\n    padding: 5px;\\r\\n    font-size: 16px;\\r\\n    text-align: right;\\r\\n\\r\\n    border-width: 0px;\\r\\n    border-bottom: 2px solid #777777;\\r\\n    outline: none;\\r\\n    transition: 1s;\\r\\n }\",\"js\":\"package al; \\npublic class CollatzConjecture { \\n  private int i = 1; \\n  public static void main(String[] args) { \\n    long l = 9999999; \\n    System.out.println(\\\"l is \\\"+ l); \\n    CollatzConjecture cc = new CollatzConjecture(); \\n    cc.Collatz(l); \\n  } \\n   \\n  /** \\n   * 至今尚未有人能證明其正確性。有趣的是，目前也尚未檢查出任何反例。 \\n   * 猜想的內容是這樣的：有一個整數，如果是偶數，就除以 2 ； \\n   * 如果是奇數，就乘以 3 再加 1 。 \\n   * 一個整數不斷這樣操作下去，最後一定會變成 1 。 \\n   * 這個操作的過程就是一種迭代。 \\n   * @author \\n   * @param param 初始輸入的數字 \\n   */ \\n  private void Collatz(long param) {    \\n    System.out.println(\\\"After \\\" + i + \\\" time we get result \\\" + param); \\n    if(param \u003e 1) { \\n      i++; \\n      if (param%2 == 0) { \\n        Collatz(param/2);         \\n      } else { \\n        Collatz(3*param + 1); \\n      } \\n    } \\n  } \\n} \"}","created_at":"2021-09-07T21:30:43.337+08:00","updated_at":"2021-09-10T19:33:36.537+08:00","name":"冰雹猜想","language":"web","screenshot":{"url":null},"parent_id":3,"plugin":"","description":null,"note":null,"status":"public","like_student_ids":[],"is_featured":false,"views":143,"hashid":"p93skvdj6","is_content_changed":false,"review_status":"unsubmitted","submitted_at":null,"reviewed_at":null,"advise":null,"is_deleted":false}